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Find the standard form of the equation of the circle with the given characteristics. Center at origin; radius: 4√2

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Answer:

x^2 + y^2 = 32

Explanation:

The fact that the circle's center is at (0,0) tells you that the circles equation is of the form x^2 + y^2 = radius^2

radius = 4*sqrt(2) Given

r^2 = (4sqrt(2) )^2

r^2 = 16 * 2

r^2 = 32

So the entire equation is

x^2 + y^2 = 32

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