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Which of the following quadratic equations has the solution (1/2,5)

User Oblador
by
8.7k points

2 Answers

5 votes

Answer:

well i got some HOPE THIS WILL HELP

Explanation:

To find the solution set of a factored quadratic equation, you should set each one of the factors equal to zero and solve for .

Lets take our first quadratic equation (x+1/2)(x-5)=0 and apply this. First we are our factors equal to zero and ; next we are going to sole for in each factor to find the solution set:

and , so the solution set for the quadratic equation (x+1/2)(x-5)=0 is

Lets do the same for our next one (x-5)(2x-1)=0

and

So, the solution set for the quadratic equation (x-5)(2x-1)=0 is

Next one (x+5)(2x-1)=0

and

So, the solution set for the quadratic equation (x+5)(2x-1)=0 is

Next one (-2x+1)(-x+5)=0

and

So, the solution set for the quadratic equation (-2x+1)(-x+5)=0 is : therefore, we are going the select this one.

Next one (x+1/2)(x+5)=0

and

So, the solution set for the quadratic equation (x+1/2)(x+5)=0 is

Finally, our last one (-2x+1)(x-5)=0

and

So, the solution set for the quadratic equation (-2x+1)(x-5)=0 is ; this is also a correct answer, make sure to select this one too.

We can conclude that both (-2x+1)(-x+5)=0 and (-2x+1)(x-5)=0 quadratic equation have as solution set.

User Brandon Joyce
by
8.0k points
6 votes

(x-5)(2x-1) (-2x+1)(-x+5)=0 and (-2x+1)(x-5)=0 quadratic equation have as solution set.

User Bulwersator
by
7.9k points

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