Question

What are the zeros of the polynomial function: f(x) = x^3 - x^2 – 6x ?

Answer 1

x=0, x=3, x=-2

Explanation:

factor the equation

x(x^2-x-6)

factor more

x(x-3)(x+2)

set it equal to 0

x(x-3)(x+2)=0

plug in numbers for x that would result in the answer being 0

0(0-3)(0+2)=0

3(3-3)(3+2)=0

-2(-2-3)(-2+2)=0