Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if: the odd digits must occupy even positions (i.e. 2nd, 4th and 6th) and the even digits must occupy

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asked Feb 17, 2020 223k views

3 votes

Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:

the odd digits must occupy even positions (i.e. 2nd, 4th and 6th) and the even digits must occupy odd positions (i.e. 1st, 3rd and 5th)

Mathematics
high-school

ShawnOrr asked

by ShawnOrr

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2 Answers

6 votes

Answer:

729 is the correct answer

Explanation:

Rey Ramos answered Feb 18, 2020

by Rey Ramos

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5 votes

the answer your looking for is 7

Arsen answered Feb 22, 2020

by Arsen

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Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if: the numbers formed must be divisible by 25 or the odd digits must occupy even positions (i.e. 2nd,

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