Question

The work of a student to solve the equation 2(5y − 2) = 12 + 6y is shown below:step 1: 2(5y − 2) = 12 + 6 step 2: 7y − 4 = 12 + 6 step 3y − 4 = 10step 4: y = 14step 5: y = 7in which step did the student first make an error and what is the correct step

Answer 1

In step 2 they added 2 and 5y instead of multiplying

Explanation:

2(5y-2)=12+6y

10y-4=12+6y

4y=16

y=4

Answer 2

Error in step 2

Explanation:

equation
`2(5y - 2) = 12 + 6y`

Given steps:

step 1: 2(5y − 2) = 12 + 6

step 2: 7y − 4 = 12 + 6

step 3y − 4 = 10

step 4: y = 14

step 5: y = 7

In step 2 , 2 is distributed inside the parenthesis. When we multiply 2 inside the parenthesis 2 times 5y is 10y

Instead of multiplying , the student added 2 and 5y and got 7y

So the error is in step 2

Step 2 should be
`10y -4= 12+6y`