Question

4x2+3x=0 please solve this by using quadratic formula

Answer 1

x= 0 and x=-3/4

Explanation:

`4x^2 + 3x =0`

We need to solve this equation using quadratic formula.

The quadratic formula is:

`x=(-b\pm√(b^2-4ac))/(2a)`

for the type of equation

`ax^2 +bx+c=0`

So, for our given equation:

a= 4

b= 3

c=0

putting values in the formula

`x=(-3\pm√(9-0))/(8)\\x=(-3\pm3)/(8)\\x=(-3+3)/(8)\,and\, x=(-3-3)/(8)\\x=(0)/(8)\,and\, x=(-6)/(8)\\x=0\,and\, x=(-3)/(4)`[/tex]

so, x= 0 and x=-3/4.