Question

Ryan bought 3 books and a magazine . He paid $30 and relieved $5 change if the magazine cost twice as much as each book, find the cost of the magazine.

please explain in algebra only :)​

Answer 1

The books are $5, and the magazines are $10. I’m not sure which way you want it explained but since magazines are twice the price of books, you can solve the equation 3b + 2b = 25. This gives you b=5 which you just multiply by 2 giving you the price of a magazine.

Answer 2

Answer: The required cost of the magazine is $10.

Step-by-step explanation: Given that Ryan bought 3 books and a magazine. He paid $30 and relieved $5 change and the magazine cost twice as much as each book.

We are to find the cost of the magazine.

Let x and y represents the cost of a book and the magazine respectively.

Then, according to the given information, we have

`3x+y=30-5\\\\\Rightarrow 3x+y=25~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)`

and

`y=2x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)`

Substituting the value of y from equation (ii) in equation (i), we get

`3x+2x=25\\\\\Rightarrow 5x=25\\\\\Rightarrow x=(25)/(5)\\\\\Rightarrow x=5`

and from equation (ii), we get

`y=2*5=10.`

Thus, the required cost of the magazine is $10.