Question

A company has designed a cylindrical tube to ship documents. To incredible the size of the tube they extended every dimension by one third of its original length After the tube is enlarged?

Answer 1

Step-by-step explanation:

You mean that every dimension is increased by 1/3, what is the change in volume?

Original tube

V = pi * r^2 * h

New Tube

V = pi * [(1 + 1/3)r]^2 * (1 + 1/3)*h

V = pi * (4/3)^2 r^2 * (4/3) * h

V = pi * (4/3)^3 r^*h

The new Tube has increased in volume by a factor of (4/3)^3 = 64/27 or approximately 2.03 times