Question

A right rectangular prism has a length of 10 in., a width of 12 in., and a height of 16 in. The dimensions of the prism are halved. What is the surface area of the reduced prism? Enter your answer in the box. in²

Answer 1

236in²

Explanation:

Given in the question,

length of rectangular prism = 10 in

width of rectangular prism = 12 in

height of the prism = 16 in

Since the dimensions are reduced to half so the new dimensions are

length of rectangular prism = 5 in

width of rectangular prism = 6 in

height of the prism = 8 in

Formula to calculate the surface area

2(lw + lh + wh)

2 ((5x6) + (8x5) + 2(6x8))

236 in²

Answer 2

`S.A=236in^2`

Explanation:

The given prism has dimension;

`L=10in.,W=12in.,H=16in.,`

If the dimensions of the prism are halved then;

`l=5in.,w=6in.,h=8in.,`

The surface area of the reduced prism will be;

`S.A=2(lw+lh+wh)`

`S.A=2(5(6)+5(8)+6(8))`

`S.A=2(30+40+48)`

`S.A=2(118)`

`S.A=236in^2`