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What is the area of the regular pentagon below

688.2 ft

850.7 ft

951.1 ft

1,376.4 ft

What is the area of the regular pentagon below 688.2 ft 850.7 ft 951.1 ft 1,376.4 ft-example-1
User Chris Chen
by
4.2k points

2 Answers

5 votes

For this case we have that by definition, the polygon area shown is given by:


A = \frac {p * a} {2}

Where:

p: It is the perimeter

a: It is the apothem

So, the perimeter is:


p = 5 * 20\\p = 100 \ ft

On the other hand, the apothem is given by:


tag (36) = \frac {10} {a}\\a = \frac {10} {tag (36)}\\a = \frac {10} {0.72654253}\\a = 13.7638191669247

Finally, the area is:


A = \frac {100 * 13.7638191669247} {2}\\A = 688.19096

Rounding off we have:
688.2 \ ft ^ 2

Answer:

Option A

User Ayinde
by
5.6k points
3 votes

Answer:

A

Explanation:

By definition, all sides of a regular polygon are equal in length. If you know the length of one of the sides, the area is given by the formula:


A=(s^2\cdot n)/(4\tan (180^(\circ))/(n)),

where s is the side length, n is the number of sides.

In your case, s=20 ft, n=5,so


A=(20^2\cdot 5)/(4\tan (180^(\circ))/(5))=(400\cdot 5)/(4\tan 36^(\circ))=(500)/(0.73)\approx 688.2\ ft^2

User S P Sharan
by
5.0k points