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(2x^2+10x+8) divided(2x+2)

1 Answer

5 votes

Answer:

x + 4

Explanation:


\mathrm{Factor}\:2x^2+10x+8:\quad 2\left(x^2+5x+4\right)\\=(2\left(x^2+5x+4\right))/(2x+2)\\\mathrm{Factor}\:2x+2:\quad 2\left(x+1\right)\\=(2\left(x^2+5x+4\right))/(2\left(x+1\right))\\=(x^2+5x+4)/(\left(x+1\right))\\\mathrm{Factor}\:x^2+5x+4:\quad \left(x+1\right)\left(x+4\right)\\\mathrm{Cancel\:the\:common\:factor:}\:x+1\\=x+4

Hope this helps and have a great day!

User Jacoballenwood
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