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If P(A)=2/3, P(B)=4/5, and P(AvB)=8/15, what is P(A^B)?

If P(A)=2/3, P(B)=4/5, and P(AvB)=8/15, what is P(A^B)?-example-1
User Maryo
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2 Answers

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Answer:

P(A^B) = 22/15 or 1 7/15

Explanation:

To find the P (A^B), we add the probability of events A and B.

2/3 + 4/5 = P, we need to find the LCD to add disimilar fractions

LCD is 15.

2(5)/15 +4(3)/15 = 10/15 + 12/15 = 22/15

User Rao Sahab
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7 votes

Answer:

A.
P(A\cap B=(14)/(15)

Explanation:

Use the formula;


P(A\cup B)=P(A)+P(B)-P(A\cap B)

It was given that;


p(A)=(2)/(3)


p(B)=(4)/(5)

and


p(A\cup B)=(8)/(15)

We substitute all these values into the formula to get;


(8)/(15)=(2)/(3)+(4)/(5)-P(A\cap B)


(8)/(15)-(2)/(3)-(4)/(5)=-P(A\cap B)

The least common denominator is 15


(8-10-12)/(15)=-P(A\cap B)


(-14)/(15)=-P(A\cap B)

Divide both sides by -1.


(14)/(15)=P(A\cap B)


P(A\cap B=(14)/(15)

User Lena Bru
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