Question

Find the Slope:

Question: hi!! I’m using the (y2-y1)/(x2-x1) formula. But I get confused because I get 0. I’ll add a picture so you can see what I’m doing.

4) (-10, 10) and (3, 10)

5) (9,4) and (25)

Answer 1

so, this is how I always do it as a little shortcut (it's the same as the formula, but it makes more sense lol):

4) 0/13 = 0 = slope

take your two points (-10, 10) and (3, 10) and just draw them relative to each other (it doesn't have to be to scale or anything)

. (-10, 10) | . (3,10)

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then, you just see how far up you go from (-10, 10) to get to (3, 10) --> look at the y-values, in this situation you do not go up or down, this means the "rise" for "rise/run" (slope) is 0

. (-10, 10) | . (3,10)

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then, you just see how far to the right you go from (-10, 10) to get to (3, 10) --> look at the x-values, in this situation you go over 13 units, this means the "run" for "rise/run" (slope) is 13

take your "rise" and your "run" and divide: 0/13 = 0**this is your slope because it is a horizontal line

5) 1/7 = slope

follow the same steps as above (just a quick little sketch on paper)

(9, 4) and (2, 5)

rise = 1

run = 7

rise/run = 1/7 = slope

Answer 2

4) slope= 0

5)
`slope = - (1)/(7)`

Explanation:

`\boxed{ slope = (y _(2) - y_1 )/(x_2 - x_1) }`

4) Slope

`= (10 - 10)/( - 10 - 3)`

`= (0)/( - 13)`

= 0

The slope is zero as the line is a horizontal line (since both points have the same y-coordinate of 10).

5) Slope

`= (5 - 4)/(2 - 9)`

`= (1)/( - 7)`

`= - (1)/(7)`

Since you have taken (x₁, y₁) to be (9, 4), the value of x₁ should be 9 instead of 2.