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A plane flies over point A going 300 m/s, 10 seconds later it flies over point B going 260m/s. 45 seconds after that it is going 350m/s. What is the plains acceleration at points B, and C? (Hint: Solve for both accelerations) (Show all work!)

User Gxc
by
5.7k points

1 Answer

1 vote

Answer:


\boxed{ \text{-4 m/s}^(2) \text{ at Point B; 2 m/s}^(2) \text{ at Point C. }}\\

Explanation:

Acceleration (a) is the change in velocity (Δv) divided by the change in time (Δt).


a = ( \Delta v )/( \Delta t ) = (v_(2) - v_(1) )/(t_(2) - t_(1)) \\

1. Acceleration at Point B


a = (260 - 300 )/(10 - 0) = (-40 )/( 10) = \text{-4 m/s}^(2)\\


\boxed{\textbf{The acceleration is -4 m/s}^(2).}\\

2. Acceleration at Point C


a = (350 - 260 )/(45 - 0) = (90 )/( 45) = \text{2 m/s}^(2)\\


\boxed{\textbf{The acceleration is 2 m/s}^(2).}\\

User Cenouro
by
5.0k points
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