Answer: The correct options are
(B) (-1, 10)
(C) (0, 7)
(E) (2, 1).
Step-by-step explanation: We are given to select all the points that lie on the graph of the following function :
![f(x)=7-3x~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iy6zfbvl5hujn6qzokjqtgp6ccvi4s2rry.png)
Option (A) : (x, f(x)) = (-2, 1).
We have
![f(-2)=7-3*(-2)=7+6=13\\eq 1.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n82o9fpzgb3xgefkfgv55gac0v8mqa0c5x.png)
So, the point (-2, 1) does not lie on the graph of equation (i).
Option (A) is incorrect.
Option (B) : (x, f(x)) = (-1, 10).
We have
![f(-1)=7-3*(-1)=7+3=10.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8mbyrhjbishx6zj6jw26untrs82mtxtibn.png)
So, the point (-2, 1) lie on the graph of equation (i).
Option (B) is correct.
Option (C) : (x, f(x)) = (0, 7).
We have
![f(0)=7-3*0=7-0=7.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/p9to122uhz5tcufv1btxc7xygxmfs7qwmv.png)
So, the point (0, 7) lie on the graph of equation (i).
Option (C) is correct.
Option (D) : (x, f(x)) = (1, 5).
We have
![f(1)=7-3*1=7-3=4\\eq 5.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dq5dac81x31fcr0mtbxdfhgg9jxz59n3q0.png)
So, the point (1, 5) does not lie on the graph of equation (i).
Option (D) is incorrect.
Option (E) : (x, f(x)) = (2, 1).
We have
![f(2)=7-3*(2)=7-6=1.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bhmrdjllil63faefwymliikwst772k7baw.png)
So, the point (2, 1) lie on the graph of equation (i).
Option (E) is correct.
Thus, options (B), (C) and (E) are correct.