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The length of a rectangle is two more than double the width. If the perimeter is 100 inches, find the

dimensions.

The length of a rectangle is two more than double the width. If the perimeter is 100 inches-example-1
User Pater
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1 Answer

14 votes
14 votes

Answer:

width = 34 inches

length = 16 inches

Explanation:

Given:

1.)The length of a rectangle is two more than double the width

2.)The perimeter is 100 inches

Let's analyze the first part,

The length is 2 more than double the width so if we let x represent the length the width would be 2x + 2

Now the second part,

the perimeter is calculated by the following formula:

2*(w+l)

(w: width, l: length)

2*(x+2x+2) first do inside the parenthesis by adding like terms

x+2x+2 = 3x + 2 now multiply both terms with 2

2*(3x+2) = 6x + 4 this is the perimeter of the rectangle, now write another equation using this

6x + 4 = 100 subtract 4 from both sides

6x = 96 divide both sides by 6

x = 16 this the length and the width would be

2x + 2 = 2*16 + 2 = 34

User Valaer
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