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Find the volume of the composite solid.

A. 702.00in^3
B. 1218.03in^3
C. 676.01in^3
D. 811.51^3

Find the volume of the composite solid. A. 702.00in^3 B. 1218.03in^3 C. 676.01in^3 D-example-1
User Santanu
by
5.4k points

2 Answers

3 votes

Answer:

The correct answer is option C. 676.01 in^3

Explanation:

It is given a composite solid.

Total volume = volume of cuboid + volume of pyramid

To find the volume of cuboid

Volume of cuboid = Base area * height

Base area = side * side = 9 * 9

Volume = 9 * 9 * 5 = 405 in^3

To find the volume of pyramid

Before that we have to find the height of pyramid

Height² = Hypotenuse² - base² = 11² - 4.5² = 100.75

Height = √100.75 = 10.03

Volume of pyramid = 1/3(base area * height)

= 1/3(9 * 9 * 10.03) = 271.01 in^3

To find the volume of solid

Volume of solid = volume of cuboid + volume of pyramid

= 405 + 271.01 = 676.01 in^3

Therefore the correct answer is option C. 676.01 in^3

User MichK
by
5.4k points
2 votes

Answer:


C.676.01 \: {in}^(3)

step-by-step explanation :

The volume of the composite solid = volume of the cuboid + volume of the rectangular pyramid

Volume of the cuboid


= L * B * H

where


L = 9 \: inches \\ B = 9 \: inches \\ H = 5 \: inches

By substitution,


\implies \: V = 5 * 9 * 9


\implies \: V = 405 \: {in}^(3)

Volume of rectangular pyramid


= (1)/(3) * base \: area * height


\implies \: V = (1)/(3) * \:( L * B ) * \: H


L = 9 \: inches \\ B = 9 \: inches \\ s= 11 \: inches

We use the Pythagoras Theorem, to obtain,

h²+4.5²=11²

h²=11²-4.5²

h=√100.75

h=10.03

By substitution,


\implies \: V = (1)/(3) * \:( 9 * 9 ) * \:10.0374

we simplify to obtain


\implies \: V =271.0098 \: {in}^(3)

Hence the volume of the the composite solid


=676.01\: {in}^(3)

User Jeff Hutchins
by
5.8k points
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