Answer:
![\boxed{15 \%}\\](https://img.qammunity.org/2020/formulas/mathematics/college/4dg1olw0h6rvopvi2aleitozw79kqvxv2s.png)
Explanation:
A. First discount
![\begin{array}{rcr}\text{ Original cost} & = &\$480.00 \\\text{ Less 30 \%} & = &-144.00 \\\text{ Sale price} & = & 336.00\\\text{ Less 2nd discount} & =& -x\\\text{ New price} & = &\$285.60 \\\end{array}\\](https://img.qammunity.org/2020/formulas/mathematics/college/znpj5g7j475rnd0tcz5vsaqc5zqo4vvefp.png)
The original price was $480.00.
The discount was 30 % calculated as
![\text{Discount } = 480.00 * (30 )/(100 )= 144.00\\](https://img.qammunity.org/2020/formulas/mathematics/college/6chu0srpjylrerbv669p4h49b9plbk53sd.png)
Subtracting that from the original price gave the sale price of $336.00.
B. Second percent discount
The second discount was
x = 336.00 – 285.60 = $50.40
The percent discount was
![\text{\% discount} = (50.40 )/(336.00 ) * 100 \% = 15 \%\\](https://img.qammunity.org/2020/formulas/mathematics/college/djofr9ti7sf5zyj2aq1fvubgtc9f167ii1.png)
![\boxed{ \text{The second percent discount was }15 \%.}\\](https://img.qammunity.org/2020/formulas/mathematics/college/z52g6jlgil9p4fk9407cy0bamsizt4x1gu.png)