Question

Two electrodes connected to a 9.0 V battery are charged to ±45 nC. What is the capacitance of the electrodes?

Answer 1

= 5 × 10^-9 F

Step-by-step explanation:

Capacitance is calculated by the formula;

C = Q/V;

where, C is the capacitance, Q is the charge in coulombs and V is the voltage across.

in this case;

Charge = ± 45 × 10^-9 Coulombs

Voltage = 9.0 V

Therefore;

Capacitance = 4.5 × 10^-8 /9

= 5 × 10^-9 F