Question

Identify any zeros of y = x2 + 4x + 5

A.(5,0),(4,0)
B. There are no zeros
C. (0,0)
D. (-1,0),(-3,0)

Help!!!!!!!!!

Answer 1

B. There are no zeros

Explanation:

`\text{The zeros for y = 0:}`

`x^2+4x+5=0\qquad\text{subtract 5 from both sides}\\\\x^2+2(x)(2)=-5\qquad\text{add}\ 2^2\ \text{to both sides}\\\\x^2+2(x)(2)+2^2=-5+2^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+2)^2=-5+4\\\\(x+2)^2=-1<0\\\\\text{Conclusion:}\\\text{No solutions}\\\\\text{Therefore your answer is B.}`

Answer 2

B. There are no zeros

Explanation:

None of the given point even lie on the parabola (curved line) of the graph, so they can't possibly be zeros. The only explanation is that there simply aren't any zeros.

So your answer is...B. There are no zeros.

Hope this helps!