Question

What is the area of the two-dimensional cross section that is parallel to face ABC ?

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ft²

Answer 1

The area of the two-dimensional cross section is
`30\ ft^(2)`

Explanation:

we know that

The two-dimensional cross section that is parallel to face ABC is a triangle congruent with the triangle ABC

Therefore

Calculate the area of triangle ABC

`A=(1)/(2)(BC)(AB)`

we have that

Triangles ABC and DEF are congruent

so

`BC=EF=12\ ft`

`AB=5\ ft`

substitute

`A=(1)/(2)(12)(5)=30\ ft^(2)`