Question

What is the electric force acting between two charges of 0.0042 C and −0.0050 C that are 0.0030 m apart?

A. −2.1 1010 N
B. 2.1 1010 N
C. 6.3 107 N
D. −6.3 107 N

Answer 1

-2.1x10^10 N

Step-by-step explanation:

Answer 2

A.−2.1 × 10^10 N

Step-by-step explanation:

Using the formula;

E = k Q1Q2/d²

Where;

E is the electrical force

k is the constant

Q1, Q2 are the two charges and

d is the distance between the two charges

Therefore;

E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²

= -2.1 x 10^10 N

Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.