Question

Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 newtons/coulomb.

A.
1.5 × 10-1 newtons
B.
9.4 × 10-7 newtons
C.
7.6 × 10-1 newtons
D.
8.7 × 10-1 newtons

Answer 1

C.

7.6 × 10-1 newtons

Step-by-step explanation:

The electrostatic force experienced by a charge is given by

`F=qE`

where

q is the magnitude of the charge

E is the magnitude of the electric field

In this problem, we have

`q=8.1\cdot 10^(-9)C` is the charge

`E=9.4\cdot 10^7 N/C` is the electric field

Substituting into the formula, we find

`F=(8.1 \cdot 10^(-9) C)(9.4\cdot 10^7 N/C)=0.76 N = 7.6\cdot 10^(-1)N`