Answer:
The average speed of the train is 45 km/h
Step-by-step explanation:
Speed
It's defined as the distance (d) per unit of time (t) traveled by an object. The formula is:
![\displaystyle v=(d)/(t)](https://img.qammunity.org/2022/formulas/mathematics/college/w5g2728rf4q8e26iyjl4qa6mbnpvuib2d5.png)
Let's call x the total distance covered by the train. It covered d1=1/3x with a speed of v1=25 km/h. The time taken is calculated solving for t:
![\displaystyle t_1=(d_1)/(v_1)](https://img.qammunity.org/2022/formulas/physics/college/2ess6qrtu94q902eesmu8puv0f7cnfqhfi.png)
![\displaystyle t_1=(1/3x)/(25)](https://img.qammunity.org/2022/formulas/physics/college/yk1cggdb1o2jl8n1fkuv0q1dzer0rd48j4.png)
![\displaystyle t_1=(x)/(75)](https://img.qammunity.org/2022/formulas/physics/college/dviqpnsaf3uangrq6byu5rlr9lwmlzb86z.png)
Now the rest of the distance:
d2 = x - 1/3x = 2/3x
Was covered at v2=75 km/h. Thus the time taken is:
![\displaystyle t_2=(d_2)/(v_2)](https://img.qammunity.org/2022/formulas/physics/college/pjg0qpfqfwzx812fc7zos3qt9e4k5zqcnk.png)
![\displaystyle t_2=(2/3x)/(75)](https://img.qammunity.org/2022/formulas/physics/college/etjlwtcmvhc7rlnm9vujwn27dtrftil0eo.png)
![\displaystyle t_2=(2x)/(225)](https://img.qammunity.org/2022/formulas/physics/college/jam5qc8cr524tukuj26cxswt5rk3o1jyjl.png)
The total time is:
![\displaystyle t_t=(x)/(75)+(2x)/(225)](https://img.qammunity.org/2022/formulas/physics/college/at4ah13ry9kbus6xwmqdrx36jirxzfszfm.png)
![\displaystyle t_t=(3x)/(225)+(2x)/(225)](https://img.qammunity.org/2022/formulas/physics/college/72v3w5y8ec3kj9cnmeokhxk9f23k7ginzg.png)
![\displaystyle t_t=(5x)/(225)](https://img.qammunity.org/2022/formulas/physics/college/6ewbw8j6ds2fozxnziah2p479l2lwhrqs4.png)
Simplifying:
![\displaystyle t_t=(x)/(45)](https://img.qammunity.org/2022/formulas/physics/college/qi3d3n3qhqxpc0qnd0l9xx4e8mr52guc4y.png)
The average speed is the total distance divided by the total time:
![\displaystyle \bar v=(x)/((x)/(45))](https://img.qammunity.org/2022/formulas/physics/college/3rppkg0s1bqpj3ouc6ttel38a4ng2onyzf.png)
Simplifying:
![\boxed{\displaystyle \bar v=45\ km/h}](https://img.qammunity.org/2022/formulas/physics/college/2xfl8xqrcqq56trph51fiqgamypp4z7cfr.png)
The average speed of the train is 45 km/h