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If θ = 72° and s = 20 cm, what is the value of t to the nearest tenth of a centimeter?

A. 13.8 cm
B. 6.2 cm
C. 21 cm
D. 6.5 cm

If θ = 72° and s = 20 cm, what is the value of t to the nearest tenth of a centimeter-example-1

2 Answers

2 votes

Answer:

c: 21 cm

Explanation:

You know
sin \theta = \frac s t. you solve for t and you get
t = \frac s {sin\theta}. place numbers.

User Dilettant
by
6.3k points
4 votes

The length of the segment t in the triangle is 21 cm

How to determine the value of t in the triangle

From the question, we have the following parameters that can be used in our computation:

The triangle

Where, we have

θ = 72° and s = 20 cm

The value of t in the triangle can be calculated using the following sine ratio

sinθ = s/t

Substitute the known values into the equation

sin(72) = 20/t

t = 20/sin(72)

Evaluate

t = 21 cm

Hence, the value of t in the triangle is 21 cm

User Nabijon
by
6.2k points