ANSWER
a) 150ft
b) 3.05s
EXPLANATION.
The quadratic function that models the height of the ball is
![h(t) = - 16.1{t}^(2) + 150](https://img.qammunity.org/2020/formulas/mathematics/middle-school/55wpkg6i7n0v4mh1mgd6ok9wp6hbo92216.png)
The ball was dropped at time t=0.
We plug in t=0 into the given function to get,
![h(0) = - 16.1{(0)}^(2) + 150](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2flhuz625hmlgajiu15qrl55va7zlsez4h.png)
![h(0) = 150](https://img.qammunity.org/2020/formulas/mathematics/middle-school/em4k853qgqi8trzpy3tvxe5aa8pxvj1xh8.png)
Therefore the ball was dropped from a height of 150 ft.
When the ball hit the ground, then h(t)=0.
This implies that:
![- 16.1{t}^(2) + 150=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6vplzv0crbh5e4y87indh8nboxc5iydrwg.png)
![- 16.1{t}^(2) =- 150](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qzvv0calsqcavy2bj79li0qqwbw2ltct0n.png)
![{t}^(2) =(- 150)/(-16.1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ve70yh04okj5zznvvrllzs1z4roz2ewrcu.png)
We take square root of both sides,
![{t} =√(9.317)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a8kup3xdqnx9qb2n6gfybeq191vm4do9as.png)
to the nearest hundredth.
Therefore the ball hit the ground after approximately 3.05 seconds.