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The quadratic function h(t) = -16.1t2 + 150 models a ball's height, in feet, over time, in seconds,

after it is dropped from a 15 story building.
From what height, in feet, was the ball dropped?
After how many seconds, rounded to the nearest hundredth, did the ball hit the ground?


2 Answers

0 votes

Answer:

A- 150

B- 3.05

Explanation:

User Notclive
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5.0k points
2 votes

ANSWER

a) 150ft

b) 3.05s

EXPLANATION.

The quadratic function that models the height of the ball is


h(t) = - 16.1{t}^(2) + 150

The ball was dropped at time t=0.

We plug in t=0 into the given function to get,


h(0) = - 16.1{(0)}^(2) + 150


h(0) = 150

Therefore the ball was dropped from a height of 150 ft.

When the ball hit the ground, then h(t)=0.

This implies that:


- 16.1{t}^(2) + 150=0


- 16.1{t}^(2) =- 150


{t}^(2) =(- 150)/(-16.1)

We take square root of both sides,


{t} =√(9.317)


{t} =3.05 to the nearest hundredth.

Therefore the ball hit the ground after approximately 3.05 seconds.

User JungleZombie
by
5.6k points