Answer:
10. 6√3; 11. ±⅛; 12. ±5⁄7
Explanation:
Exercise 10 is not simplified all the way because when trying to find the square root of a non-perfect square like 12, you need to find two numbers that multiply to it, where one number is a non-perfect square, and the other obviously has to be a perfect square. Those numbers are 3 and 4. The square root of 4 is 2, which gets moved to the outside along with 3, so you would multiply the two outside terms to get 6. Then √3 would stay as is because there is NO perfect square that would be capable of factoring that out any longer. So, your answer is 6√3.
For the last two, you simply take the square root of both the denominator and numerator [BOTH NEGATIVE AND POSITIVE].
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