Answer:
Ted's claim is correct
Explanation:
Opposite sides of a parallelogram are congruent, so AC≅DE and AD≅CE. Opposite sides of a rectangle are congruent, so AB≅DC and AD≅BC. By the transitive property of congruence BC≅AD≅CE, so BC≅CE. ΔABC≅ΔDCE by SSS congruence.