Question

15 POINTS - What is the value of the expression when y=2? See image.

Answer 1

6

Explanation:

The given expression is;

`(2-y)/(4+y)+(3(y+2))/(y)`

When y=2, the expression becomes;

`(2-2)/(4+2)+(3(2+2))/(2)`

This simplifies to;

`(0)/(6)+(3(4))/(2)`

`0+3(2)`

Multiply to get;

`0+6=6`

The value of the expression when y=2 is 6.