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Use the discriminant to determine the number of real solutions to the quadratic equation. n^2 − n − 6 = 0 What is the number of real solutions? Select the correct answer below:

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2 Answers

5 votes

ANSWER

2

EXPLANATION

The given quadratic equation is


{n}^(2) - n - 6 = 0

Comparing to


a{n}^(2) + b n + c = 0

We have a=1, b=-1 and c=-6

The discriminant is given by the formula,


D = {b}^(2) - 4ac

Plug in the values to get,


D = {( - 1)}^(2) - 4(1)( - 6)


D =1 + 24 = 25

Since the discriminant is positive, the equation has two real roots.

User Tommaso Taruffi
by
8.4k points
3 votes

Answer: last option

Explanation:

The formula to find the Discriminant is:


D=b^2-4ac

Given the quadratic equation
n^2-n-6=0, you can identify that:


a=1\\b=-1\\c=-6

Now, you can substitute values into the formula
D=b^2-4ac, then:


D=b^2-4ac\\D=(1)^2-4(1)(-6)\\D=25

As the Discriminant is greater than 0 (
D>0), then the quadratic equation
n^2-n-6=0 has two distinct real solutions.

User Adrion
by
8.4k points