Answer:
(4.9793, 6.2207)
Explanation:
Given the data:
Sample size, n = 34
Sample mean, m = 5.6
Standard deviation, s = 2.2
Confidence interval = 90%
Using the relation :
m ± Zcritical * s/√n
Zcritical at 90% confidence interval = 1.645
Confidence interval ;
5.6 ± (1.645 * 2.2/√34)
5.6 ± 0.6206533
Lower boundary = 5.6 - 0.6206533 = 4.9793
Upper boundary = 5.6 + 0.6206533 = 6.2207