Question

What is the perimeter of kite OBDE?

Answer 1

the best answer would be 27 units i hope this helps chu

Answer 2

The correct option is 3. The perimeter of kite OBDE is 27 units.

Explanation:

From the figure it is clear that the triangle ABC is right angled triangle.

According to Pythagoras theorem,

`hypotenuse^2=perpendicular^2+base^2`

Using Pythagoras theorem, we get

`AB^2=AC^2+BC^2`

`AB=√((15)^2+(8)^2)`

`AB=17`

The diameter of circle of is 17 units. So, the radius of the circle is

`(17)/(2)=8.5`

Angle DBO and DEO are right angles it means DB and DE are tangent.

According to the circle tangent theorem the length of tangent from the same point are equal.

`DB=DE=5`

`r=OB=OE=8.5`

Perimeter of kite OBDE is

`Perimeter(OBDE)=OB+DB+DE+OE`

`Perimeter(OBDE)=8.5+5+5+0.8=27`

The perimeter of kite OBDE is 27 units. Therefore the correct option is 3.