Question

You mix 55 mL of 1.00 M silver nitrate with 25 mL of 0.84 M sodium chloride. What mass of silver chloride should you form

Answer 1

mass of silver chloride (AgCl) = 3.0135 grams

Step-by-step explanation:

The chemical equation is:

`AgNO_(3(aq)) + NaCl_((aq)) \to AgCl_((s)) + NaNo_3_(aq))`

No. of mole = molarity × volume

For AgNO3:

No. of moles = 1.00 × 0.055

= 0.055 moles

No. of moles of NaCl = 0.84 × 0.025

= 0.021 moles

From the equation:

`1 \ mol e \ of \ AgNO_3 \ react \ with \ 1 \ mole \ o f \ NaCl`

Therefore, 0.055 moles of AgNO3 react with 0.055 moles of NaCl

Here;

NaCl serves as the limiting reactant

Thus,

1 mole of NaCl will react with AgNO3 to yield 1 mole of AgCl

∴

0.021 moles of NaCl react with AgNO3 to yield 0.021 moles og AgCl

mass of AgCl = no of moles × molar mass

= 0.021 × 143.5

= 3.0135 grams