Hello!
If a solution containing 75 mL of alcohol has a percent by volume of 50%. What is the total volume of the solution ?
We have the following information:
% v/v (percentage of volume per volume) = 50
V1 (solute volume) = 75 mL
V (volume of the solution) = ? (in mL)
We apply the data to the formula of volume percentage of the solute per volume of solution, we will have:
![\%\:v/v = (v_1)/(v) *100](https://img.qammunity.org/2020/formulas/chemistry/middle-school/pn1mbioy069zka158x6duyuetjjy7fb0lj.png)
![50 = (75)/(v)*100](https://img.qammunity.org/2020/formulas/chemistry/middle-school/g1c043r1322mc8obdmvz94vmos83fezk2x.png)
multiply the means by the extremes
![50*v = 75*100](https://img.qammunity.org/2020/formulas/chemistry/middle-school/n1a2m907ja2sts2o5sc9hihxn6fflp168y.png)
![50\:v = 7500](https://img.qammunity.org/2020/formulas/chemistry/middle-school/284qfybxcrw8gkigf6dwdsi1r4ta0ffhif.png)
![v = (750\diagup\!\!\!\!0)/(5\diagup\!\!\!\!0)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/qia6m1f5yyj7fczwckt8poq0r98c7d2c0i.png)
![\boxed{\boxed{v = 150\:mL}}\Longleftarrow(volume\:of\:solution)\:\:\:\:\:\:\bf\green{\checkmark}](https://img.qammunity.org/2020/formulas/chemistry/middle-school/m4mr94n1rar1v2j8dd72gv91weslg5kr0f.png)
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