Question

A 9.5 v battery supplies a 2.0 ma current to a circuit for 6.0 h . you may want to review (page) . for help with math skills, you may want to review: conversion between seconds and hours part a how much charge has been transferred from the negative to the positive terminal

Answer 1

= 43.2 Coulombs

Step-by-step explanation:

Using the formula;

Q = it

where Q is the charge in coulombs

I is the current in Amperes and

t is the time is seconds

I = 2.0 mA = 0.002 A

t = 6.0 h = 6 × 3600 seconds

Therefore;

Q = 0.002 × 6 × 3600 s

= 43.2 Coulombs

Therefore the charge that has been transferred from the negative to the positive terminal is 43.2 coulombs.