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Find the x-intercept(s) of y = 2x2 - 3x - 5.

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Answer:

see explanation

Explanation:

To find the x- intercepts, set y = 0, that is

2x² - 3x - 5 = 0

To factorise the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

The factors are + 2 and - 5

Use these factors to split the x- term

2x² + 2x - 5x - 5 = 0 ( factor the first/second and third/fourth terms )

2x(x + 1) - 5(x + 1) = 0 ← factor out (x + 1) from each term

(x + 1)(2x - 5) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1 ⇒ (- 1, 0)

2x - 5 = 0 ⇒ 2x = 5 ⇒ x =
(5)/(2) ⇒ (
(5)/(2), 0)

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