Question

A gas mixture consists of 60.0% Ar, 30.0% Ne, and 10.0% Kr by volume. If the pressure of this gas mixture is 80.0 kPa, what is the partial pressure of each of the gases

Answer 1

Answer: The partial pressure of Argon , Neon and krypton are 48 kPa , 24 kPa and 8 kPa respectively.

Step-by-step explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

`p_A=x_A* P_(total)`

where,
`p_A` = partial pressure of component A

`x_A` = mole fraction of A

`P_(total)` = total pressure

mole fraction of Ar =
`\frac{\text {Moles of Ar}}{\text {total moles}}=(60.0)/(60.0+30.0+10.0)=0.6`

`p_(Ar)=0.60* 80.0kPa=48kPa`

mole fraction of Ne =
`\frac{\text {Moles of Ne}}{\text {total moles}}=(30.0)/(60.0+30.0+10.0)=0.30`

`p_(Ne)=0.30* 80.0kPa=24kPa`

mole fraction of Kr =
`\frac{\text {Moles of Kr}}{\text {total moles}}=(10.0)/(60.0+30.0+10.0)=0.10`

`p_(Kr)=0.10* 80.0kPa=8kPa`