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The average of five unequal positive integers is 11. What is the largest possible value that any of those numbers can have?

User Amit Aviv
by
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1 Answer

3 votes

Answer:

45

Explanation:

The smallest ones can be 1, 2, 3, 4, so the largest will be ...

(1 + 2 + 3 + 4 + n)/5 = 11 . . . . the average of the 5 integers

10 + n = 55

n = 45

The largest one can be 45.

User Manish Silawat
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