Question

Is (0,0) a solution to this system?

Answer 1

The correct answer is option D

No. (0, 0) satisfy y ≥ x² + 2x -4 but does not satisfy y > x² + 2x + 1

Explanation:

It is given two inequalities

y ≥ x² + 2x -4

y > x² + 2x + 1

Check (0, 0) satisfy the inequalities

1). y ≥ x² + 2x -4

0 ≥ 0² + 2*0 -4

0 ≥ -4

It is true

2). y > x² + 2x + 1

0 > 0² + 2*0 + 1

0 > 1

It is not true

The correct answer is option D

No. (0, 0) satisfy y ≥ x² + 2x -4 but does not satisfy y > x² + 2x + 1

Answer 2

D. (0,0) satisfies y ≥ x² + x = 4

Explanation:

To see if the value pair (0,0), verifies an inequation, we simply have to replace the variables x and y by their values (in this case x=0 and y=0) and see what the final calculation is.

Let's start with the first one:

y ≥ x² + x - 4

If we replace variables by their value, we get:

0 ≥ 0² + 0 - 4

Which is the same as

0 ≥ -4

Which is TRUE, so (0,0) does verify the first inequation.

Let's see for the second one:

y > x² + 2x +1

0 > 0² + 2(0) + 1

0 > 1

Which is FALSE, so (0,0) does NOT verify the second inequation.