Question

Find the area of the shaded region. Round to the nearest tenth.

Answer 1

(shaded area) = (area of circle section 360-130 degrees) + (isosceles triangle)

(section area 230 degrees) =
`(230^\circ)/(360^\circ)\pi r^2= 0.6389\cdot 3.1416\cdot 123.21 m^2 = 247.3m^2`

(triangle area) =
`(1)/(2)a\cdot b\cdot\sin 130^\circ = (1)/(2)11.1^2 m^2\cdot\sin 130^\circ=47.19m^2`

(Total area) = 247.3 + 47.2 = 294.5 m^2