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If ab = 8 and a^2 + b^2 = 16, then what is the value of (a+b)^2?

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User RFG
by
8.0k points

2 Answers

1 vote

Answer:

32

Explanation:

Note that

(a + b)² = a² + 2ab + b²

= a² + b² + 2ab ← substitute given values for a² + b² and ab

= 16 + (2 × 8)

= 16 + 16

= 32

User Kora
by
7.4k points
4 votes

Answer:

32

Explanation:

(a+b)²=a²+2ab+b²=(a²+b²)+2ab=16+2*8=32

User Vlad Jerca
by
8.2k points

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