Question

A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each.A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each.A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each.A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each.

Answer 1

Snail's speed =
`(30m)/(2400s)` = 0.0125m/s

Turtle's speed =
`(330m)/(2400s)` = 0.1375m/s

Step-by-step explanation:

Let the snail's speed be x m/s

The turtle's speed then is 11x m/s

Speed = Distance ÷ Time

Since speed and distance are directly proportional;

The ratio of the distances snail and turtle cover before they meet is x:11x respectively.

Simplified, the ratio of snail distance : turtle distance = 1:11

So snail covers a distance of
`(1)/(12)` × 360 = 30m

And turtle covers a distance of
`(11)/(12)` × 360 = 330m

The time each took before they met is 40 × 60 = 2400 seconds

Snail's speed =
`(30m)/(2400s)` = 0.0125m/s

Turtle's speed =
`(330m)/(2400s)` = 0.1375m/s