Question

What is the specific heat of a 123 g substance that requires 4.56 J of heat in

order to increase its temperature by 12.32 °C?

A) 0.00301 J/g °C

B) 0.457 J/g °C

0 6910 J/g °C

D) 2.19 J/g °C

E) 0.0220 J/g°C

Answer 1

Answer: A.
`0.00301J/g^0C`

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat absorbed = 4.56 J

m = mass of substance = 123 g

c = specific heat capacity = ?

Change in temperature ,
`\Delta T=T_f-T_i=12.32^0C`

Putting in the values, we get:

`4.56J=123g* c* 12.32^0C`

`c=0.00301J/g^0C`

The specific heat of a 123 g substance that requires 4.56 J of heat in order to increase its temperature by 12.32 °C is
`0.00301J/g^0C`