Question

3.0 L of a gas is at a temperature of 78 degrees Celsius. Find the volume of the gas at standard temperature

Answer 1

= 2.33 L

Step-by-step explanation:

Using the Charles law.

V1/T1 = V2/T2

V1 = 3.0 L

T1 = 78 + 273

= 351 K

At s.t.p the temperature is 273 K and pressure is 1 atm.

V2 = ?

T2 = 273 K

V2 = V1T2/T1

= (3.0 ×273)/351

= 2.33 L