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33 votes
33 votes
What are the rational roots for the polynomial shown below?
x³ + 5x²-8r-20=0

User Rocketsarefast
by
2.7k points

1 Answer

9 votes
9 votes


x ^(3) + 5x {}^(2) - 8 r - 20 = 0 \\ x { }^(3) + 5x {}^(2) - 8r - 20(x {}^(3) + 5x {}^(2) ) = 0 - (x {}^(3) + 5x {}^(2) ) \\ - 8r - 20 = - (x {}^(3) + 5x {}^(2) ) \\ \\ - 8r - 20 + 20 = - (x {}^(3 ) + 5x {}^(2) ) + 20 \\ \\ - 8r = x {}^(3) - 5x {}^(2) + 20 \\ \\

hope it is helpful

User DarkWanderer
by
3.4k points
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