Question

A small glass bead has been charged to 8.0 nC (nano-Coulombs). What is the magnitude of the electric field 2.0 m from the center of the bead

Answer 1

Given :

Charge on glass bead, Q = 8 nC .

To Find :

The magnitude of the electric field 2.0 m from the center of the bead.

Solution :

Electric field at position r is given by :

`E = (kQ)/(r^2)\\\\E = (9* 10^9* 8* 10^(-9))/(2^2)\\\\E = 18\ N/C`

Therefore, the magnitude of the electric field 2.0 m from the center of the bead is 18 N/C .