Question

PLEASE HELP ASAP!!! WILL GIVE MORE POINTS IF ANSWERED QUICKLY!!!

Emily leaves her house at 8:25 a.m to bike to her school, which is 3.42 miles away. When she passes the post office, which is 3/4 mile away from her home, she looks at her watch and sees that it is 30 seconds past 8:29 a.m.


If Emily's school starts at 8:50 a.m., can Emily make it to school on time without increasing her rate of speed? Show/and explain the work necessary to support your answer.

Answer 1

From 8:25 to 30 seconds past 8:29 is 4.5 minutes.

This means she rode her bike 3/4 mile in 4.5 minutes.

Calculate her speed per mile:

1 mile / 0.75 = 1.333

4.5 minutes * 1.333 = 6 minutes per mile.

She needs to ride 3.42 miles, so multiply distance by speed:

3.42 miles x 6 minutes per mile = 20.52 minutes.

0.52 * 60 = 31.2 seconds.

This means it will take a total of 20 minutes and 31 seconds to get from her house to school.

She left at 8:25, add her travel time:

8:25 + 20 minutes and 31 seconds = 8:45 and 31 seconds.

This is sooner than the time school starts so she makes it on time.