Question

3690 J of heat are added to a 21.5 g sample

of iron at 30◦C. What is the final temperature of the iron? The specific heat of iron is

0.449 J/g · K.

Answer in units of K.


PLEASE HELP BEEN STUCK ON THIS FOR FOUR DAYS THXS

Answer 1

693K

Step-by-step explanation:

The enthalpy change in the iron is 3690J

We now apply the formula for enthalpy change which is ΔH=mC∅ where ∅ is the temperature change, m the mass of the substance, and C the specific heat capacity for the substance.

ΔH in this case is 3690J.

Therefore 3690J=21.5g×0.449J/g.K×∅

as we are looking for ∅, we make it the subject of the formula.

∅=3690J/(21.5g×0.44J/g)

∅=390

Temperature=30°C +390

=420°+273

=693K