Question

If an instant pot has an internal pressure of 191.0 kPa, temperature of 750.0 K and a volume of 6.5 L, how many moles of gas would be contained inside the instant pot?

Answer 1

0.200 mol.

Step-by-step explanation:

Hello!

In this case, since this case is considered an ideal one (no intermolecular interactions), we can use the following equation:

`PV=nRT`

Thus, since we know the pressure, temperature and volume, we are able to compute the moles shown below:

`n=(PV)/(RT) =(191kPa*(1000Pa)/(1kPa) *6.5L*(1m^3)/(1000L) )/(8.314(Pa*m^3)/(mol*K)*750.0K)\\\\n=0.200mol`

Best regards!