Question

6. Balsa wood with an average density of 130 kg/m3 is floating in pure water. What percentage of the wood is submerged

Answer 1

Archimedes' Principle dictates that the percentage of balsa wood submerged in water is the density of the wood divided by the density of water, multiplied by 100%. With a wood density of 130 kg/m3 and water density of 1000 kg/m3, the calculation shows that 13% of the balsa wood is submerged.

Step-by-step explanation:

The question involves applying Archimedes' Principle to determine what percentage of balsa wood is submerged when floating in pure water. According to Archimedes' Principle, the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. In the case of floating objects, the weight of the displaced fluid is equal to the weight of the object. For balsa wood with an average density of 130 kg/m3 floating in pure water with a density of 1000 kg/m3, the fraction of the volume of wood submerged is equal to the ratio of the density of the wood to the density of the water.

Therefore, the percentage submerged is given by the following calculation:

Percentage submerged = (Density of wood / Density of water) * 100%

Percentage submerged = (130 kg/m3 / 1000 kg/m3) * 100%

Percentage submerged = 13%

Thus, 13% of the balsa wood is submerged when it floats in pure water.

Answer 2

The percentage of the submerged wood is 13%.

Step-by-step explanation:

Given;

density of the Balsa wood,
`\rho _(wood)` = 130 kg/m³

density of pure water,
`\rho_(water)` = 1000 kg/m³

The percentage of the submerged wood is calculated as;

`Percentage \ of \ submerged \ wood = (130 \ kg/m^3)/(1000 \ kg/m^3) \ * \ 100 \% \\\\Percentage \ of \ submerged \ wood = 13 \ \%`

Therefore, the percentage of the submerged wood is 13%.